How to round a floating point to nearest 10?

[Edwin.Madari at VerizonWireless.com]

>>> round(76.1, -2)
100.0
>>> round(76.1, -1)
80.0
>>> round(76.1)    
76.0
>>> 

builtin function round,  will work for you......
Help on built-in function round in module __builtin__:
round(...)
    round(number[, ndigits]) -> floating point number
    
    Round a number to a given precision in decimal digits (default 0 digits).
    This always returns a floating point number.  Precision may be negative.

good luck..
Edwin

-----Original Message-----
From: python-list-bounces+edwin.madari=verizonwireless.com at python.org
[mailto:python-list-bounces+edwin.madari=verizonwireless.com at python.org]
On Behalf Of John Machin
Sent: Saturday, August 09, 2008 5:54 PM
To: python-list at python.org
Subject: Re: How to round a floating point to nearest 10?


On Aug 10, 1:19 am, Mensanator <mensana... at aol.com> wrote:
> On Aug 9, 6:31 am, Will Rocisky <geekm... at gmail.com> wrote:
>
> > I want my 76.1 to be rounded to decimal 80 and 74.9 to decimal 70.
> > How can I achieve that?
> >>> print '%.0e' % 74.9
> 7e+01
> >>> print '%.0e' % 76.1
>
> 8e+01

But:
>>> print '%.0e' % 176.1
2e+002

Giving the Subject ("How to round a floating point to nearest 10?"),
there's a strong presumption that the OP would want the answer to be
180, not 200.
--
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