Self-referencing decorator function parameters

[castironpi at gmail.com]

On Apr 2, 7:30 am, Thomas Dimson <tdim... at gmail.com> wrote:
> Hello,
>
> Originally I posted this as a bug but it was shot down pretty quickly.
> I am still mildly curious about this as I'm missing a bit of
> understanding of Python here. Why is it that the following code
> snippet:
>
> def decorator( call ):
>     def inner(func):
>         def application( *args, **kwargs ):
>             call(*args,**kwargs)
>             func(*args,**kwargs)
>         return application
>
>     return inner
>
> class DecorateMe:
>     @decorator( call=DecorateMe.callMe )
>     def youBet( self ):
>         pass
>
>     def callMe( self ):
>         print "Hello!"
>
> DecorateMe().youBet()
>
> Will not compile, giving:
> Traceback (most recent call last):
>   File "badpython.py", line 10, in <module>
>     class DecorateMe:
>   File "badpython.py", line 11, in DecorateMe
>     @decorator( call=DecorateMe.callMe )
> NameError: name 'DecorateMe' is not defined
>
> Where if you change the "call=DecorateMe.callMe" to "call=lambda x:
> DecorateMe.callMe(x)" everything goes along its merry way. Nesting the
> call in a lambda seems to allow it to recognize the class definition.
> Any ideas as to what is going on here (other than ugly code)?

def decorator( call ):
    def inner(func):
        def application( *args, **kwargs ):
            call(*args,**kwargs)
            func(*args,**kwargs)
        return application


    return inner


class DecorateMe:


    def callMe( self ):
        print( "Hello!" )
    @decorator( call=callMe )
    def youBet( self ):
        pass

DecorateMe().youBet()