a name error

[Paul Scott]

On Tue, 2008-04-15 at 13:54 +0800, Penny Y. wrote:
> import urllib2,sys
> try:
>     r=urllib2.urlopen("http://un-know-n.com/")
> except URLError,e:
>     print str(e)
>     sys.exit(1)
> 
> print r.info()
> 
> 
> But got the errors:
> 
> Traceback (most recent call last):
>   File "t1.py", line 4, in ?
>     except URLError,e:
> NameError: name 'URLError' is not defined
> 
> 
> Why these is not the name of URLError? I saw it on this module's page:

You need to define the urllib first.

url=urllib2
try:
    r=urllib2.urlopen("http://un-know-n.com/")
except url.URLError,e:
    print str(e)
    sys.exit(1)

print r.info()

You can't just launch into a catchable exception without first defining
something.

--Paul
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