learning with python question (HtTLaPP)

[umpsumps at gmail.com]

ok.. I finally made something that works.. Please let me know what you
think:

>>> def lines(letters):
	fin = open('words.txt')
	count = 0
	rescount = 0  # count the number of results
	results = ""  # there are words that contain the letters
	for line in fin:
		needs = 0
		x = str(line.strip())
		for ch in letters:
			if ch not in x:
				pass
			else:
				needs = needs + 1
		if needs == len(letters):
			rescount += 1
			results = results + '\n' + x
		count += 1
	print count, 'lines searched'
	print results, '\n'
	print 'result count is: ', rescount


On Apr 26, 4:02 pm, "Eric Wertman" <ewert... at gmail.com> wrote:
> >  Is the way I wrote the function inherently wrong?  What I wrote
>
> I would not say that.  I think a lot of people probably start off like
> that with python.  You'll find in most cases that manually keeping
> counters isn't necessary.  If you really want to learn python though,
> I would suggest using built in functions and libraries as much as
> possible, as that's where the real power comes from (IMO).
>
> >  returns the sequence, however I'm trying to make the output match for
> >  the letters in the string entered, not necessarily the string
> >  sequence.
> >  Only the sequence shows up 'uzi'.  I don't get words like 'unzip' or
> >  'Zurich' .  I've only barely started on invocation and maybe writing
> >  something like I'm describing is above what level I'm currently at.
>
> This would be a more difficult approach..   Where you are doing the
> comparison step:
>
> if letters in line.strip():
>
> It's trying to match the exact string "uzi", not any of the individual
> letters.  You would need to look for each letter independently and
> then make sure they were in the right order to match the other words.