PROBLEMS WITH PYTHON IN SOME VARIABLE,FUNCTIONS,ETC.

[Vladimir Kropylev]

yes, ths is known problem. I can just recomend you to use Linux or
FreeBSD, though cygwin maybe also possible


2008/4/8, subhabrata.iisc at hotmail.com <subhabrata.iisc at hotmail.com>:
> I am using Python 2.5.1 (r251:54863, Apr 18 2007, 08:51:08) [MSC v.
>  1310 32 bit (Intel)] on win32 with IDLE 1.2.1
>  My O/S is Windows XP SP2 I use 512 MB RAM.
>  I am encountering the following problems:
>  (i) a1=1
>     a2=2
>     a3=a1+a2
>     print a3
>  # The result is coming sometimes as 3 sometimes as vague numbers.
>
>  (ii) x1="Bangalore is called the Silicon Valley of India"
>     x2="NewYork"
>     x3=x1.find(x2)
>     print x3
>  # The result of x3 is coming as -1 as well as +ve numbers.
>
>  (iii) I have been designing one crawler using "urllib". For crawling
>  one web page it is perfect. But when I am giving around 100 URLs by
>  and their links and sublinks the IDLE is not responding. Presently I
>  have been running with 10 URLs but can't it be ported?
>
>  (iv) I have designed a program with more than 500 if elif else but
>  sometimes it is running fine sometimes it is giving hugely erroneous
>  results, one view of the code:
>  elif a4==3:
>         print "YOU HAVE NOW ENTERED THREE WORDS"
>         if a3[0] not in a6:
>             if a3[1] not in a6:
>                 if a3[2] not in a6:
>                     print "a3[0] not in a6, a3[1] not in a6, a3[2] not
>  in a6"
>                 elif a3[2] in a6:
>                     print "a3[0] not in a6, a3[1] not in a6, a3[2] in
>  a6"
>                 else:
>                     print "NONE3.1"
>             elif a3[1] in a6:
>                 if a3[2] not in a6:
>                     print "a3[0] not in a6, a3[1] in a6, a3[2] not in
>  a6"
>                 elif a3[2] in a6:
>                     print "a3[0] not in a6,a3[1] in a6, a3[2] in a6"
>                 else:
>                     print "NONE3.2"
>             else:
>                 print "NONE3.3"
>         elif a3[0] in a6:
>             if a3[1] not in a6:
>                 if a3[2] not in a6:
>                     print "a3[0] in a6, a3[1] not in a6, a3[2] not in
>  a6"
>                 elif a3[2] in a6:
>                     print "a3[0] in a6, a3[1] not in a6, a3[2] in a6"
>                 else:
>                     print "NONE3.4"
>             elif a3[1] in a6:
>                if a3[2] not in a6:
>                    print "a3[0] in a6, a3[1] in a6, a3[2] not in a6"
>                elif a3[2] in a6:
>                    print "a3[0] in a6, a3[1] in a6, a3[2] in a6"
>                else:
>                    print "NONE3.5"
>             else:
>                 print "NONE3.6"
>         else:
>             print "NONE3.7"
>  Why it is behaving like that?
>  If someone can help me.
>  Best Regards,
>  Subhabrata Banerjee,
>  Indian Institute of Science,
>  Bangalore,
>  India.
>
> --
>  http://mail.python.org/mailman/listinfo/python-list
>