Autogenerate functions (array of lambdas)

[Chris Johnson]

What I want to do is build an array of lambda functions, like so:

a = [lambda: i for i in range(10)]

(This is just a demonstrative dummy array. I don't need better ways to
achieve the above functionality.)

print [f() for f in a]

results in: [9, 9, 9, 9, 9, 9, 9, 9, 9, 9]
rather than the hoped for: [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

Clearly, lambda is returning the object i, which is left at the last
value of range(10). The following is my solution.

t = lambda i: lambda: i
a = [t(i) for i in range(10)]

or the somewhat more terse:

a = [(lambda i: lambda: i)(i) for i in range(10)]

This gives the behavior which, intuitively, I expected from the
original syntax. So my questions are:
1) Does this make sense as what should be done here? That is, would
this be the behavior you'd want more often than not? As I said,
intuitively, I would think the lambda would treat the iterator
variable as a constant in this context.
2) Is there a better or preferred method than the one I've found?

Thanks,
Chris