recursion
Neil Cerutti
horpner at yahoo.com
Thu Sep 13 13:32:38 EDT 2007
On 2007-09-13, Ian Clark <iclark at mail.ewu.edu> wrote:
> Neil Cerutti wrote:
>> On 2007-09-13, Gigs_ <gigs at hi.t-com.hr> wrote:
>>> Can someone explain me this
>>>
>>>>>> def f(l):
>>> if l == []:
>>> return []
>>> else:
>>> return f(l[1:]) + l[:1] # <= cant figure this, how is all sum at the end?
>>
>> In plain English, the above program says:
>>
>> The sum of the items in list l is zero if the list is empty.
>> Otherwise, the sum is the value of the first item plus the sum of
>> the rest of the items in the list.
>
> Am I missing something? What does this have to do with summing?
>
> >>> def f(l):
> ... if l == []:
> ... return []
> ... else:
> ... return f(l[1:]) + l[:1]
> ...
> >>> f([1, 2, 3, 4])
> [4, 3, 2, 1]
It says: You need to read more than the first sentence of a
message before responsing:
> Well, it would say that if it weren't somewhat buggy. l[:1]
> doesn't evaluate to a number, but to a list containing one
> number, so the above program doesn't do what you say it does.
>
> It should read something like:
>
> def my_sum(seq):
> if len(seq) == 0:
> return 0
> else:
> return seq[0] + my_sum(seq[1:])
--
Neil Cerutti
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