Factory function with keyword arguments

[Ron Adam]

Steven D'Aprano wrote:
> I'm writing a factory function that needs to use keywords in the produced 
> function, not the factory. Here's a toy example:


> I thought of doing this:
> 
> def factory(flag):
>     if flag: kw = 'spam'
>     else: kw = 'ham'
>     def foo(obj, arg):
>         kwargs = dict([(kw, arg)])
>         return obj.method(**kwargs)
>     return foo
> 
> Is this the best way of doing this? Are there any alternative methods 
> that aren't risky, slow or obfuscated?

Looks ok to me.  It can be simplified a bit.

    def factory(flag):
        kw = 'spam' if flag else 'ham'
        def foo(obj, arg):
            return obj.method(**{kw:arg})
        return foo


Cheers,
    Ron