startswith( prefix[, start[, end]]) Query
Tim Williams
listserver at tdw.net
Thu Sep 6 11:29:47 EDT 2007
On 06/09/07, Bruno Desthuilliers
<bruno.42.desthuilliers at wtf.websiteburo.oops.com> wrote:
>
> You may want to try with a regexp, but I'm not sure it's worth it (hint:
> the timeit module is great for quick small benchmarks).
>
> Else, you could as well write your own testing function:
>
> def str_starts_with(astring, *prefixes):
> startswith = astring.startswith
> for prefix in prefixes:
> if startswith(prefix):
> return true
> return false
>
> for line in f:
> if str_starts_with(line, 'abc, 'de', 'xxx'):
> # CODE HERE
>
Isn't slicing still faster than startswith? As you mention timeit,
then you should probably add slicing to the pot too :)
if astring[:len(prefix)] == prefix:
do_stuff()
:)
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