HTTP Protocol Client

[thanosv at gmail.com]

On Sep 19, 6:10 am, welcomestocont... at gmail.com wrote:
>  Hi,
>
> I am writing http protocol to get some data from servers. If i was
> using my localhost, getting replay from local and if want access other
> remote sites, i am getting error. Please reply it
>
> My localhost client script:::
>
> Code: ( python )
>
> import httplib
>
> h = httplib.HTTP('localhost',80)
>
> h.putrequest('GET','')
>
> h.putheader('User-Agent','Lame Tutorial Code')
>
> h.putheader('Accept','text/html')
>
> h.endheaders()
>
> errcode,errmsg, headers = h.getreply()
>
> print errcode,errmsg, headers
>
> f = h.getfile() # Get file object for reading data
>
> data = f.read()
>
> print data
>
> f.close()
>
> the Reply getting from this::::
>
> 403 Forbidden Date: Tue, 18 Sep 2007 05:20:36 GMT
>
> Server: Apache/2.0.52 (Red Hat)
>
> Accept-Ranges: bytes
>
> Content-Length: 3985
>
> Connection: close
>
> Content-Type: text/html; charset=UTF-8
>
> And some Html script
>
> If I want to access other sites:::
>
> import httplib
>
> h = httplib.HTTP('http://Google.com',80)
>
> h.putrequest('GET','')
>
> h.putheader('User-Agent','Lame Tutorial Code')
>
> h.putheader('Accept','text/html')
>
> h.endheaders()
>
> errcode,errmsg, headers = h.getreply()
>
> print errcode,errmsg, headers
>
> f = h.getfile() # Get file object for reading data
>
> data = f.read()
>
> print data
>
> f.close()
>
> I got the error like:::
>
> Traceback (most recent call last):
> File "c.py", line 6, in ?
> h.endheaders()
> File "/usr/lib/python2.3/httplib.py", line 712, in endheaders
> self._send_output()
> File "/usr/lib/python2.3/httplib.py", line 597, in _send_output
> self.send(msg)
> File "/usr/lib/python2.3/httplib.py", line 564, in send
> self.connect()
> File "/usr/lib/python2.3/httplib.py", line 532, in connect
> socket.SOCK_STREAM):
> socket.gaierror: (-2, 'Name or service not known')
>
> How can I access Remote sites using http protocol . I did'nt write
> server script.
>
> Thanks And Regards
> Allavarapu

1. First try setting the debug level with
h.set_debuglevel(9)
2. nslookup or dig google.com
3. are you behind a firewall ?

4. why not just use urllib.urlopen ? Its a lot easier and sets up all
the headers, and yes it can do POSTs.