Newbi Q: Recursively reverse lists but NOT strings?
Gary Herron
gherron at islandtraining.com
Mon Oct 15 02:30:18 EDT 2007
Dmitri O.Kondratiev wrote:
>
> The function I wrote (below) reverses lists all right:
>
> def reverse(xs):
> if xs == []:
> return []
> else:
> return (reverse (xs[1:])) + [xs[0]]
>
>
> >>> reverse ([1,2,3])
> [3, 2, 1]
> >>>
>
>
> Yet when I try to reverse a string I get:
>
> >>> reverse ("abc")
>
> ...
> ...
> ...
>
> File "C:\wks\python-wks\reverse.py", line 5, in reverse
>
> return (reverse (xs[1:])) + [xs[0]]
>
> File "C:\wks\python-wks\reverse.py", line 5, in reverse
>
> return (reverse (xs[1:])) + [xs[0]]
>
> File "C:\wks\python-wks\reverse.py", line 2, in reverse
>
> if xs == []:
>
> RuntimeError: maximum recursion depth exceeded in cmp
>
> >>>
>
> What's wrong? Why recursion never stops?
>
If you are doing this as an python-learning exercise, then read on. If
you are doing this reversal for real code, then try:
xs.reverse() for in-place reversal of a list (but not a string), or
result = xs[::-1] for creating a reversed copy of either a string or a
list
Your recursion stops when xs == [], but when you're stripping characters
off a string, like 'abc', the remaining portion will be 'bc', then 'c',
than '', but never [] so you 'll never stop.
Try:
if xs == []:
return []
elif xs == '':
return ''
else:
...
Gary Herron
>
> Thanks,
> Dima
More information about the Python-list
mailing list