Newbi Q: Recursively reverse lists but NOT strings?
Dmitri O.Kondratiev
dokondr at gmail.com
Mon Oct 15 05:38:32 EDT 2007
Gary, thanks for lots of info!
Python strings are not lists! I got it now. That's a pity, I need two
different functions: one to reverse a list and one to reverse a string:
def reverseList(xs):
if xs == []:
return xs
else:
return (reverseList (xs[1:])) + [xs[0]]
def reverseStr(str):
if str == "":
return str
else:
return (reverseStr (str[1:])) + str[0]
Ok. Now regarding in-place reversal of a list:
>>> l = [1,2,3]
>>> l
[1, 2, 3]
>>> l.reverse()
>>> l
[3, 2, 1]
That was, as I expected. Good.
Then why this ? :
>>> ls = [1,2,3].reverse()
>>> ls
>>>
>>> print [1,2,3].reverse()
None
>>>
I mean, why ls is empty after assignment?
Also, I couldn't find in the Python docs what this form of slicing means:
xs[::-1] ?
It works for creating a reversed copy of either a string or a list, but what
does '::-1' syntax means?
Thanks,
Dmitri O. Kondratiev
dokondr at gmail.com
http://www.geocities.com/dkondr
On 10/15/07, Gary Herron <gherron at islandtraining.com> wrote:
>
> Dmitri O.Kondratiev wrote:
> >
> > The function I wrote (below) reverses lists all right:
> >
> > def reverse(xs):
> > if xs == []:
> > return []
> > else:
> > return (reverse (xs[1:])) + [xs[0]]
> >
> >
> > >>> reverse ([1,2,3])
> > [3, 2, 1]
> > >>>
> >
> >
> > Yet when I try to reverse a string I get:
> >
> > >>> reverse ("abc")
> >
> > ...
> > ...
> > ...
> >
> > File "C:\wks\python-wks\reverse.py", line 5, in reverse
> >
> > return (reverse (xs[1:])) + [xs[0]]
> >
> > File "C:\wks\python-wks\reverse.py", line 5, in reverse
> >
> > return (reverse (xs[1:])) + [xs[0]]
> >
> > File "C:\wks\python-wks\reverse.py", line 2, in reverse
> >
> > if xs == []:
> >
> > RuntimeError: maximum recursion depth exceeded in cmp
> >
> > >>>
> >
> > What's wrong? Why recursion never stops?
> >
> If you are doing this as an python-learning exercise, then read on. If
> you are doing this reversal for real code, then try:
>
> xs.reverse() for in-place reversal of a list (but not a string), or
> result = xs[::-1] for creating a reversed copy of either a string or a
> list
>
>
> Your recursion stops when xs == [], but when you're stripping characters
> off a string, like 'abc', the remaining portion will be 'bc', then 'c',
> than '', but never [] so you 'll never stop.
>
> Try:
>
> if xs == []:
> return []
> elif xs == '':
> return ''
> else:
> ...
>
>
> Gary Herron
>
>
> >
> > Thanks,
> > Dima
>
>
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