Problem using subprocess.Popen on windows

[Nicholas Bastin]

On 10/7/07, jorma kala <jjkk73 at gmail.com> wrote:
>  from subprocess import *
>
>  p1 = Popen(["dir"],  stdout=PIPE)
>  output = p1.communicate()[0]
>
>
>  But I get a WindowsError : [Error 2]  File Not Found

Tim answered your actual question, but why are you doing this in the
first place?  The Python standard library provides all the
functionality that dir will provide and you don't have to parse the
output...

Look into <http://www.python.org/doc/lib/os-file-dir.html>, and
specifically, os.listdir(path).

--
Nick