No module named urllib
HMS Surprise
john at datavoiceint.com
Mon May 7 19:41:49 EDT 2007
On May 7, 6:31 pm, Jorge Godoy <jgo... at gmail.com> wrote:
> HMS Surprise <j... at datavoiceint.com> writes:
> > Since sys.path = ['.', 'C:\\maxq\\lib\\Lib', 'C:\\maxq\\jython'] I
> > copied urllib to c:\maxq\lib\Lib.
>
> > Now I get the error -
>
> > Traceback (innermost last):
> > File "<string>", line 5, in ?
> > File "C:\maxq\lib\Lib\urllib.py", line 1148
> > _hextochr = dict(('%02x' % i, chr(i)) for i in range(256))
> > ^
> > SyntaxError: invalid syntax
> >>> dict(1, 1)
>
> Traceback (most recent call last):
> File "<stdin>", line 1, in <module>
> TypeError: dict expected at most 1 arguments, got 2
>
> >>> dict(a=1)
> {'a': 1}
>
> --
> Jorge Godoy <jgo... at gmail.com>
Using the 18.5.2 Examples and a few lines added in
from CompactTest import CompactTest
import sys
print sys.path
import urllib
class login(CompactTest):
# Recorded test actions.
def runTest(self):
self.msg('Test started')
opener = urllib.FancyURLopener({})
f = opener.open("http://www.python.org/")
f.read()
# Code to load and run the test
if __name__ == 'main':
login('login').Run()
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