itertools.groupby

[Steve Howell]

--- Alex Martelli <aleax at mac.com> wrote:

> Steve Howell <showell30 at yahoo.com> wrote:
>    ...
> > for has_chars, frags in itertools.groupby(lines,
> > lambda x: len(x) > 0):
> 
> Hmmm, it appears to me that itertools.groupby(lines,
> bool) should do
> just the same job, just a bit faster and simpler,
> no?
> 

Agreed.  

I updated the webpages with your change (after testing
it in 2.5):

http://wiki.python.org/moin/SimplePrograms




       
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