Is it possible to determine what a function needs for parameters -

[rh0dium]

On May 2, 7:49 am, Bruno Desthuilliers <bruno.
42.desthuilli... at wtf.websiteburo.oops.com> wrote:

> Yes - using inspect.getargspec. I don't have example code at hand yet,
> but it's not really complicated.

Viola!! Hey this works!!  Now I have modified my code to do this - way
cool (still kind of a mess though)

            args, varargs, varkw, defs =
inspect.getargspec(self.function)
            # Deal with just some args
            if varargs is None and varkw is None:
                result=self.function(input)
            # Deal with *args
            if varkw is None and varargs is not None and len(args) >
0:
                result=self.function(input[0:-1], *input[-1])
            if varkw is None and varargs is not None and len(args)==0:
                result=self.function(*input[0])
            # Deal with *kwargs
            if varkw is not None and varargs is not None and len(args)
> 0:
                result=self.function(input[0:-2], *input[-2],
**input[-1])
            if varkw is not None and varargs is not None and
len(args)==0:
                result=self.function(*input[-2], **input[-1])
            if varkw is not None and varargs is None and len(args) >
0:
                result=self.function(input[0:-1], **input[-1])
            if varkw is not None and varargs is None and len(args) ==
0:
                result=self.function(**input[0])

Now this worked until I threw a function which looked like this

def func5( input1, input2, input3 )
    pass

So it barfed because of this..

if varargs is None and varkw is None:
   result=self.function(input)

but all of the parameters were lumped as a list so input1 contained
them all...
A small tweak turned into this..
            if varargs is None and varkw is None:
                if isinstance(input, tuple):
                    result=self.function(*input)
                else:
                    result=self.function(input)

But now I suppose I need to do this for all of them but that will
break my other logic...

Yuck - I have to be missing something here.