dislin titlin and string decode
Gabriel Genellina
gagsl-py2 at yahoo.com.ar
Sat May 19 17:43:50 EDT 2007
En Sat, 19 May 2007 18:28:51 -0300, luis <solisgb at gmail.com> escribió:
> The problem was the value of dislin.chacod. This must be 'ISO1' not
> the default ('STANDAR')
I used to use DISLIN some time ago, but now I use PyChart most of the
time. Its convoluted interfase (mostly due to Fortran support, I guess)
makes it rather "ugly" to use from Python. (And has a very strange
licence, btw.)
--
Gabriel Genellina
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