dislin titlin and string decode

Gabriel Genellina gagsl-py2 at yahoo.com.ar
Sat May 19 17:43:50 EDT 2007


En Sat, 19 May 2007 18:28:51 -0300, luis <solisgb at gmail.com> escribió:

> The problem was the value of dislin.chacod. This must be 'ISO1' not
> the default ('STANDAR')

I used to use DISLIN some time ago, but now I use PyChart most of the  
time. Its convoluted interfase (mostly due to Fortran support, I guess)  
makes it rather "ugly" to use from Python. (And has a very strange  
licence, btw.)

-- 
Gabriel Genellina




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