How to convert a number to binary?

[Michael Bentley]

On May 17, 2007, at 6:45 PM, Lyosha wrote:

> On May 17, 4:40 pm, Michael Bentley <mich... at jedimindworks.com> wrote:
>> On May 17, 2007, at 6:33 PM, Lyosha wrote:
>>
>>> Converting binary to base 10 is easy:
>>>>>> int('11111111', 2)
>>> 255
>>
>>> Converting base 10 number to hex or octal is easy:
>>>>>> oct(100)
>>> '0144'
>>>>>> hex(100)
>>> '0x64'
>>
>>> Is there an *easy* way to convert a number to binary?
>>
>> def to_base(number, base):
>>         'converts base 10 integer to another base'
>>
>>         number = int(number)
>>         base = int(base)
>>         if base < 2 or base > 36:
>>                 raise ValueError, "Base must be between 2 and 36"
>>         if not number:
>>                 return 0
>>
>>         symbols = string.digits + string.lowercase[:26]
>>         answer = []
>>         while number:
>>                 number, remainder = divmod(number, base)
>>                 answer.append(symbols[remainder])
>>         return ''.join(reversed(answer))
>>
>> Hope this helps,
>> Michael
>
> That's way too complicated...  Is there any way to convert it to a  
> one-
> liner so that I can remember it?  Mine is quite ugly:
>     "".join(str((n/base**i) % base) for i in range(20) if n>=base**i)
> [::-1].zfill(1)

to_base(number, 2) is too complicated?