Rats! vararg assignments don't work
samwyse
dejanews at email.com
Wed May 30 06:05:05 EDT 2007
Gary Herron wrote:
> samwyse wrote:
>
>>I'm a relative newbie to Python, so please bear with me. After seeing
>>how varargs work in parameter lists, like this:
>> def func(x, *arglist):
>>and this:
>> x = func(1, *moreargs)
>>I thought that I'd try this:
>> first, *rest = arglist
>>Needless to say, it didn't work. That leaves me with two questions.
>>
>>First, is there a good way to do this? For now, I'm using this:
>> first, rest = arglist[0], arglist[1:]
>>but it leaves a bad taste in my mouth.
>>
>
> Well, your moreargs parameter is a tuple, and there are innumerable ways
> to process a tuple. (And even more if you convert it to a list.)
My use-case is (roughtly) this:
first, *rest = f.readline().split()
return dispatch_table{first}(*rest)
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