How to copy a ClassObject?

[Karlo Lozovina]

Duncan Booth <duncan.booth at invalid.invalid> wrote in
news:Xns98F995B5964F6duncanbooth at 127.0.0.1: 

> Consider yourself corrected.
> 
> You could do what you are attempting with:
> 
>    tmp = new.classobj('tmp', First.__bases__, dict(First.__dict__))
> 
> which creates a new class named 'tmp' with the same base classes and
> a copy of First's __dict__ except that the __name__ attribute for the
> new class will be set to 'tmp'. The attribute values are still shared
> between the classes (which is significant only if they are mutable),
> but otherwise they won't be sharing state.
> I have no idea why you would want to do this, nor even why you would
> want a   'name' attribute when Python already gives you '__name__'.

First of all, thanks for a clarification. 'name' attribute was just a 
(dumb) example, it was the first thing to come to mind.

The idea behind all of this was to create classes dynamicaly, without 
knowing in advance their names, or base class(es). So I figured I'd just 
copy the base class and modify the attributes. 
Instead, this way of subclassing seems to work just right for my purposes.

-- 
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