Passing arguments to a command line from a python script

[zacherates]

On Mar 19, 9:42 pm, "Luis M. González" <luis... at gmail.com> wrote:
> On Mar 19, 9:25 pm, "Gabriel Genellina" <gagsl-... at yahoo.com.ar>
> wrote:
>
>
>
> > En Mon, 19 Mar 2007 20:46:56 -0300, Luis M. González <luis... at gmail.com>
> > escribió:
>
> > > What I want now is execute the script I just created.
> > > As far as I know, the only way to execute the script is from a command
> > > line and typing "setup.py py2exe".
>
> > A few ways:
> > - os.system("commandline"). Simplest way, but you don't have much control,
> > and it blocks until the process finishes.
> > - os.popen[234]? or the functions in the popen2 module
> > - the subprocess module - the most complete way, but simple enough for
> > most cases.
>
> > --
> > Gabriel Genellina
>
> I'm sorry, but still I can't figure out this...
> Would you please show me a sample usage of os.system or os.popen for
> passing arguments to the command line?
> In this case, I should pass to the command line "setuppy py2exe".
>
> Thanks!
> Luis

aaron at athena:~$ python
Python 2.4.4c1 (#2, Oct 11 2006, 21:51:02)
[GCC 4.1.2 20060928 (prerelease) (Ubuntu 4.1.1-13ubuntu5)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import os
>>> rt = os.system("ls")
apps       Firefox_wallpaper.png  s2        tux_sshot_0.ppm
xorg.conf.diff
Desktop    media                  s3        work
downloads  permutation.py         squeak    workspace
Examples   permutation.pyc        trackers  xorg.conf.aiglx
>>> rt
0
>>>

This implies that `os.system("setuppy py2exe")` should do what you
want.