Link Dictionary

[James Stroud]

anush shetty wrote:
> On Jun 12, 2:10 am, James Stroud <jstr... at mbi.ucla.edu> wrote:
> 
>>anush shetty wrote:
>>
>>>Hi,
>>>I have two dictionaries
>>
>>> dict1={'B8': set(['I8', 'H8', 'B2', 'B7', 'F8', 'C9', 'G8', 'B4',
>>>'B5', 'B6', 'C8', 'E8', 'D8', 'B3', 'A9', 'A8', 'C7', 'B9', 'A7',
>>>'B1']), 'B9': set(['I9', 'H9', 'A7', 'F9', 'B3', 'B6', 'G9', 'B4',
>>>'B5', 'C9', 'B7', 'E9', 'B1', 'B2', 'D9', 'A9', 'A8', 'C8', 'B8',
>>>'C7']), 'D1': set(['F1', 'F2', 'F3', 'G1', 'I1', 'D2', 'H1', 'A1',
>>>'D4', 'B1', 'D8', 'D9', 'D6', 'D7', 'C1', 'D5', 'E1', 'D3', 'E3',
>>>'E2'])}
>>
>>>and
>>>dict2=
>>>{'I6': '0', 'H9': '9', 'I2': '0', 'E8': '0', 'H3': '0', 'H7': '0',
>>>'I7': '3', 'I4': '0', 'H5': '0', 'F9': '0', 'G7': '5', 'G6': '9',
>>>'G5': '0', 'E1': '7', 'G3': '2', 'G2': '0', 'G1': '0', 'I1': '0',
>>>'C8': '0', 'I3': '5', 'E5': '0', 'I5': '1', 'C9': '0', 'G9': '0',
>>>'G8': '0', 'A1': '0', 'A3': '3', 'A2': '0', 'A5': '2', 'A4': '0',
>>>'A7': '6', 'A6': '0', 'C3': '1', 'C2': '0', 'C1': '0', 'E6': '0',
>>>'C7': '4', 'C6': '6', 'C5': '0', 'C4': '8', 'I9': '0', 'D8': '0',
>>>'I8': '0', 'E4': '0', 'D9': '0', 'H8': '0', 'F6': '8', 'A9': '0',
>>>'G4': '6', 'A8': '0', 'E7': '0', 'E3': '0', 'F1': '0', 'F2': '0',
>>>'F3': '6', 'F4': '7', 'F5': '0', 'E2': '0', 'F7': '2', 'F8': '0',
>>>'D2': '0', 'H1': '8', 'H6': '3', 'H2': '0', 'H4': '2', 'D3': '8',
>>>'B4': '3', 'B5': '0', 'B6': '5', 'B7': '0', 'E9': '8', 'B1': '9',
>>>'B2': '0', 'B3': '0', 'D6': '2', 'D7': '9', 'D4': '1', 'D5': '0',
>>>'B8': '0', 'B9': '1', 'D1': '0'}
>>
>>>Now I want to create a dict which would have both the keys and values
>>>to be of the corresponding values of dict2.
>>
>>>Something like this:
>>
>>>Eg. The first key in dict1 i.e. B8 as 0 (0 is the value of B8 in
>>>dict2) mapped as set(['0','0','0',...]).
>>
>>>Can anyone help me out with this.
>>>-
>>>Anush
>>
>>new_dict = {}
>>for akey, aset in dict1.items():
>>   new_dict[akey] = sum(int(dict2[k]) for k in aset)
>>
>>James
> 
> 
> 
> So there is no way I can represent all the duplicates right.
> 
> So is there any solution where I could take the values of dictionary
> and represent them separately?
> 
> -
> Anush
> 

Just leave off the sum and turn the generator into a list comprehension:

new_dict = {}
for akey, aset in dict1.items():
    new_dict[akey] = [dict2[k] for k in aset]

James