Floating Number format problem

Marc Christiansen usenet at solar-empire.de
Tue Jun 12 06:04:44 EDT 2007


Gabriel Genellina <gagsl-py2 at yahoo.com.ar> wrote:
> En Tue, 12 Jun 2007 05:46:25 -0300, <kelvin.you at gmail.com> escribió:
> 
>> On 6 12 ,   3 16 , ici <iltch... at gmail.com> wrote:
>>> On Jun 12, 10:10 am,                 <kelvin.... at gmail.com> wrote:
>>>
>>> > How could I format the float number like this: (keep 2 digit
>>> > precision)
>>> > 1.002 => 1
>>> > 1.12  => 1.12
>>> >>> print "%.02f" % (2324.012)
>>> 2324.01
>>>
>> But in these case:
>>
>>>>> print '%.02f'%1.002
>> 1.00
>>>>> print '%.02f'%1.00
>> 1.00
>>
>> I just expect it to output "1" , but these way will output 1.00
> 
> def my_formatter_ommitting_trailing_zeroes(value):
>   result = '%.2f' % value
>   if result[-3:]=='.00': result = result[:-3]
>   return result
> 
> for f in [1.0, 1.002, 1.12, 1.567, 2324.012]:
>   print "%g -> %s" % (f, my_formatter_ommitting_trailing_zeroes(f))

Or:

def my_other_formatter_ommitting_trailing_zeroes(value):
    result = '%.2f' % value
    return result.rstrip('0.')

my_other_formatter_ommitting_trailing_zeroes(1.102) == "1.1"



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