Integer division

[jm.suresh@no.spam.gmail.com]

On Jun 7, 2:15 pm, Hamish Moffatt <ham... at cloud.net.au> wrote:
> jm.sur... at no.spam.gmail.com wrote:
> > Hello all,
> >  I have two integers and I want to divide one by another, and want to
> > get an integer result which is the higher side whenever the result is
> > a fraction.
> >  3/2 => 1 # Usual behavior
> >  some_func(3, 2) => 2 # Wanted
>
> > Any easier solution other than int(math.ceil(float(3)/2))
>
> The normal solution is to add (divisor-1) to the dividend before division.
>
> Ie ceil(3/2) = floor((3+(2-1))/2) = 2. Correct.
>
> But ceil(4/2) = floor((4+(2-1))/2) = 2 also. Correct.
>
> Hamish

What about this?

>>> def div_ceil(a, b):
...     if a%b:
...         return ((a/b)+1)
...     else:
...         return (a/b)
...
>>> div_ceil(3,2)
2
>>> div_ceil(-3,2)
-1
>>> -3%2
1
>>> -(3%2)
-1
>>> div_ceil(-5,2)
-2
>>> div_ceil(5,2)
3