a=0100; print a ; 64 how to reverse this?

[mosi]

Thank you,
this is great,
I thought that this should be standard in python 2.4 or 2.5 or in some
standard library (math ???)
Didn`t find anything.


On Jul 17, 2:05 pm, John Machin <sjmac... at lexicon.net> wrote:
> On Jul 17, 9:09 pm, mosi <skawan... at gmail.com> wrote:
>
>
>
> > Problem:
> > how to get binary from integer and vice versa?
> > The simplest way I know is:
> > a = 0100
> > a
> > 64
>
> > but:
> > a = 100 (I want binary number)
> > does not work that way.
>
> > a.__hex__   exists
> > a.__oct__ exists
>
> > but where is a.__bin__ ???
>
> > What`s the simplest way to do this?
> > Thank you very much.
>
> Here's a sketch; I'll leave you to fill in the details -- you may wish
> to guard against interesting input like b < 2.
>
> >>> def anybase(n, b, digits='0123456789abcdef'):
>
> ...    tmp = []
> ...    while n:
> ...       n, d = divmod(n, b)
> ...       tmp.append(digits[d])
> ...    return ''.join(reversed(tmp))
> ...>>> anybase(1234, 10)
> '1234'
> >>> anybase(7, 2)
> '111'
> >>> [anybase(64, k) for k in range(2, 17)]
>
> ['1000000', '2101', '1000', '224', '144', '121', '100', '71', '64',
> '59', '54', '4c', '48', '44', '40']
>
>
>
> HTH,
> John