How to create new files?

[ahlongxp]

On Jul 13, 5:14 am, Robert Dailey <rcdai... at gmail.com> wrote:
> Hi,
>
> I'm trying to create a Python equivalent of the C++ "ifstream" class,
> with slight behavior changes.
>
> Basically, I want to have a "filestream" object that will allow you to
> overload the '<<' and '>>' operators to stream out and stream in data,
> respectively. So far this is what I have:
>
> class filestream:
>         def __init__( self, filename ):
>                 self.m_file = open( filename, "rwb" )
>
> #       def __del__( self ):
> #               self.m_file.close()
>
>         def __lshift__( self, data ):
>                 self.m_file.write( data )
>
>         def __rshift__( self, data ):
>                 self.m_file.read( data )
>
> So far, I've found that unlike with the C++ version of fopen(), the
> Python 'open()' call does not create the file for you when opened
> using the mode 'w'. I get an exception saying that the file doesn't
> exist. I expected it would create the file for me. Is there a way to
> make open() create the file if it doesn't exist, or perhaps there's
> another function I can use to create the file? I read the python docs,
> I wasn't able to find a solution.
>
using "w" or "wb" will create new file if it doesn't exist.
at least it works for me.
> Also, you might notice that my "self.m_file.read()" function is wrong,
> according to the python docs at least. read() takes the number of
> bytes to read, however I was not able to find a C++ equivalent of
> "sizeof()" in Python. If I wanted to read in a 1 byte, 2 byte, or 4
> byte value from data into python I have no idea how I would do this.
>
f.read(10) will read up to 10 bytes.
you know what to do now.

> Any help is greatly appreciated. Thanks.

and another thing to mention, __del__() will not always be called( any
comments?).
so you'd better flush your file explicitely by yourself.

--
ahlongxp

Software College,Northeastern University,China
ahlongxp at gmail.com
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