SyntaxError: 'return' outside function
Melih Onvural
melih.onvural at gmail.com
Wed Jan 31 16:25:02 EST 2007
Has anyone seen this error before and been able to solve it? I can't
seem to find anything that leads to a solution. I found this post
http://zope.org/Collectors/Zope/1809, but can't really understand it.
I've attached my code below to see if anything looks funny. It happens
at the very last return at the end. Thanks in advance,
--melih
===========Code========
def legiturl(self, url):
# this breaks down the url into 6 components to make sure it's
"legit"
t = urlparse.urlparse(url)
if t[0] != 'http':
return ""
# remove URL fragments, but not URL
if len(t[5]) > 0:
url = urlparse.urlunparse((t[0],t[1],t[2],"","",""))
t = urlparse.urlparse(url)
# stupid parser sometimes leaves frag in path
x = find(t[2], '#')
if x >= 0:
return ""
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