importing / loading a module / class dynamically

[hg]

Laszlo Nagy wrote:

> 
>> .../.../../plugin/name1/name1.py
>> ....
>> .../.../../plugin/namen/namen.py
>>
>>
>> I block at the beginning and tried this (test.py is a real file)
>>   
>>>>> s = 'test.py'
>>>>> eval ('import ' + s)
>>>>>         
> import test.py  # This is invalid
> import test # This MAY be valid
> import name1.name1 # Most probably this is what you want if you have the
> aforementioned directory stucture
> from name1 import name1 # Or this?
> 
> You must also:
> 
> 1. Have the 'plugin' dir in your sys.path
> 2. Have at least an empty plugin/name1/__init__.py file
> 
> Another alternative is to have plugins/__init__.py and do something like:
> 
> from plugins.name1 import name1
> 
> You should not overcomplicate things anyway. If you do not need these
> name1...namen directories for sure, then just drop them.
> 
> Hint: try this (untested)
> 
> import os
> fnames = os.listdir('plugins')
> for fname in fnames:
>     if os.path.isdir(fname):
>        root,ext = os.path.splitext(fname)
>        cmd = "from plugins.%s import %s" % (root,root)
>        print "I should eval this:",cmd
> 
> Best,
> 
>    Laszlo
> 
> 
>> Traceback (most recent call last):
>>   File "<pyshell#1>", line 1, in -toplevel-
>>     eval ('import ' + s)
>>   File "<string>", line 1
>>     import test.py
>>


Thanks,

What I am doing is adding plugin support to PyCrust ... so I'm looking for a
mechanism where anyone can develop a plugin and have it loaded by pycrust.

the .py was a typo 


why the "...Have at least an empty plugin/name1/__init__.py file..." ?

Thanks,

hg