Yet another unique() function...

MonkeeSage MonkeeSage at gmail.com
Wed Feb 28 16:43:12 EST 2007


Paul,

In your case optimized version, in the second try clause using
itertools, it should be like this, shouldn't it?

return t(g.next()[1] for k,g in groupby(s, lambda (i,v): v))
                 ^^^

Regards,
Jordan




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