converting u'11\xa022' to '11\xa022'
alf
ask at me
Tue Feb 20 19:12:42 EST 2007
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converting u'11\xa022' to '11\xa022'
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Hi, is there a more elegant way to do that: ''.join([chr(ord(i)) for i in u'11\xa022' ]) -- thx, alf
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converting u'11\xa022' to '11\xa022'
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converting u'11\xa022' to '11\xa022'
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