Tkinter __call__
Gigs_
gigs at hi.t-com.hr
Fri Feb 16 07:09:27 EST 2007
James Stroud wrote:
> Gigs_ wrote:
>> from Tkinter import *
>> from tkFileDialog import askopenfilename
>> from tkColorChooser import askcolor
>> from tkMessageBox import askquestion, showerror
>> from tkSimpleDialog import askfloat
>>
>> demos = {
>> 'Open': askopenfilename,
>> 'Color': askcolor,
>> 'Query': lambda: askquestion('Warning', 'You typed
>> "..."\nConfirm?'),
>> 'Error': lambda: showerror('Error!', "He's dead, Jim"),
>> 'Input': lambda: askfloat('Entry', 'Enter credit card number')
>> }
>>
>>
>> class Demo(Frame):
>> def __init__(self, parent=None):
>> Frame.__init__(self, parent)
>> self.pack()
>> Label(self, text="Basic demos").pack()
>> for (key, value) in demos.items():
>> func = (lambda key=key: self.printit(key))
>> Button(self, text=key, command=func).pack(side=TOP,
>> fill=BOTH)
>> def printit(self, name):
>> print name, 'returns =>', demos[name]()
>>
>>
>> I have tried but cant get it to work properly.
>> I want to instead printit method to put __call__ and call it like that
>> Can someone help me, please?
>
> The code you have should work. My guess is that you don't understand
> lambda and so you want to do it a "different" way, using a "callable"?
> Well, that's what lambda does, it makes a callable object:
>
>
> Python 2.5 (r25:51918, Sep 19 2006, 08:49:13)
> [GCC 4.0.1 (Apple Computer, Inc. build 5341)] on darwin
> Type "help", "copyright", "credits" or "license" for more information.
> py> key = 1
> py> callable(lambda key=key: self.printit(key))
> True
> py> '__call__' in dir(lambda key=key: self.printit(key))
> True
>
>
>
> So the code you have already does what you want to do. Maybe understand
> what you are studying before you reinvent the wheel--you will save
> yourself a lot of frustration.
>
> James
I understand lambda, and I know that code is working. But want to do for
exercise with __call__. This coed is from programming python 2ed boo
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