How to make this Python code print blocks of text?

[Chris]

On Dec 20, 9:00 pm, chriswilliams <chriswilliam... at yahoo.com> wrote:
> This code prints output in rows like this:
> ******
> ******
> ******
> How to make print in blocks like this?
> ***** ***** ******
> ***** ***** ******
> ***** ***** *****
>
> start= int (raw_input("StartTable?"))
> upperlimit= int (raw_input ("FinalTable?"))
> cycle= start
> while cycle <= upperlimit:
> .......table= cycle
> .......counter= 0
> .......while counter < 10:
> ..............counter= counter + 1
> ..............print table, "X", counter, "=", counter * table
> .......cycle= cycle + 1
>
> The program prints multyply tables like this
> 4 X1 = 4
> 4 X2 = 8
> 5 X 1= 5
> 5 X 2= 10
> 6 X1= 6
> 6 X2= 12
> etc.
>
> And needs to print like this:
> 4 X1 = 4.....5 X 1= 5...... 6 X 1= 1
> 4 X2 = 8..... 5 x 2=10..... 6 X 2= 12
>
> Thanks in advance for any help

The reason for it printing on multiple lines is because the print
statement adds a newline character to the end of the existing line.
You can get around this by throwing times table into a list and then
joining them.

for x in xrange(start, (upperlimit+1)):
    print '...'.join(['%i X %i = %i'%(x, j, (x*j)) for j in
xrange(1,11)])

Some things to remember, rather use iterators than creating them
yourself with integer variables and incrementing them.  Also the
easier syntax for incrementing counters yourself is 'counter += 1'
instead of the uglier 'counter = counter + 1'.
For the string you are printing, look into string formatting rather
than dumping things like 'print table, "X", counter, "=", counter *
table' as "print '%i X %i = %i' % (table, counter, (table*counter))"
is so much neater and easier to comprehend especially if you end up
with a long ass string all muddled together.

HTH,
Chris