Zipfile content reading via an iterator?

[Gabriel Genellina]

En Tue, 11 Dec 2007 17:14:14 -0300, Tim Chase  
<python.list at tim.thechases.com> escribi�:

> I'm dealing with several large items that have been zipped up to
> get quite impressive compression.  However, uncompressed, they're
> large enough to thrash my memory to swap and in general do bad
> performance-related things.  I'm trying to figure out how to
> produce a file-like iterator out of the contents of such an item.

The Time Machine in action again - that's already done, but in SVN. You  
want the new ZipFile.open(filename) method, which returns a file-like  
object.
Either wait until the 2.6 release, or get the zipfile.py source from  
http://svn.python.org/view/python/trunk/Lib/zipfile.py and see if it works  
with the current 2.5 release. (I think it should work OK)

-- 
Gabriel Genellina