Help: Trouble with imp.load_module

[David Hirschfield]

I'm not entirely sure what's going on here, but I suspect it's related 
to my general lack of knowledge of the python import internals.

Here's the setup:

module: tester.py:
-----------------
import imp
def loader(mname, mpath):
    fp, pathname, description = imp.find_module(mname,[mpath])
    try:
        m = imp.load_module(mname, fp, pathname, description)
    finally:
        if fp:
            fp.close()
    return m

module = loader("testA","/path/to/testA/)
print module.test_func("/path/to/something")

module = loader("test.B","/path/to/test.B/")
print module.test_func("/path/to/something")
------------------


module: testA.py:
---------------
def test_func(v):
    import os
    return os.path.exists(v)
---------------

module: test.B.py:
---------------
def test_func(v):
    import os
    return os.path.exists(v)
---------------


Okay, so modules "testA.py" and "test.B.py" are functionally identical, 
except for the name of the module files themselves, and this is the 
important part. The tester.py module is a really simple rig to run 
"imp.load_module" on those two files.

You should get no problem running the first test of module "testA.py" 
but you should get a traceback when attempting to run the second module 
"test.B.py":

Traceback (most recent call last):
  File "tester.py", line 15, in ?
    print module.test_func("/path/to/something")
  File "./test.B.py", line 2, in test_func
    import os
  File "/usr/lib/python2.4/os.py", line 131, in ?
    from os.path import curdir, pardir, sep, pathsep, defpath, extsep, 
altsep
ImportError: No module named path


So this must have something to do with the "." in the name of module 
"test.B.py" but what is the problem, exactly? And how do I solve it? I 
will sometimes need to run load_module on filenames which happen to have 
"." in the name somewhere other than the ".py" extension. Is the 
find_module somehow thinking this is a package?

Any help would be appreciated,
-Dave

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