Escaping the semicolon?

[Sergio Correia]

On Dec 4, 2007 10:40 AM, Nick <nickjbyrne at gmail.com> wrote:


> Is this expected behavior?
>
> >>> s = '123;abc'
> >>> s.replace(';', '\;')
> '123\\;abc'
>

Everything is Ok. It's still a single backslash. Try:

>>> print  s.replace(';', '\;')

Or
>>> x = s.replace(';', '\;')
>>> print x

Best,
Sergio
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