Seek the one billionth line in a file containing 3 billion lines.

[Bjoern Schliessmann]

Peter Otten wrote:

> n = 10**9 - 1
> assert n < sys.maxint
> f = open(filename)
> wanted_line = itertools.islice(f, n, None).next()
> 
> should do slightly better than your implementation.

It will do vastly better, at least in memory usage terms, because
there is no memory eating range call.

Regards,


Björn

-- 
BOFH excuse #31:

cellular telephone interference