regexp problem in Python

Sat Aug 4 06:22:53 EDT 2007

On 4 A ustos, 00:41, Ehsan <ehsan.khod... at gmail.com> wrote:
> I want to find "http://www.2shared.com/download/1716611/e2000f22/
> Jadeed_Mlak14.wmv?tsid=20070803-164051-9d637d11"  or 3gp instead of
> wmv in the text file like this :
> <html>
> ""some code""
> function reportAbuse() {
>     var windowname="abuse";
>     var url="/abuse.jsp?link=" + "http://www.2shared.com/file/1716611/
> e2000f22/Jadeed_Mlak14.html";
>     OpenWindow =
> window.open(url,windowname,'toolbar=no,scrollbars=no,resizable=no,width=500,height=500,left=50,top=50');
>     OpenWindow.focus();
>   }
>   function startDownload(){
>     window.location = "http://www.2shared.com/download/1716611/
> e2000f22/Jadeed_Mlak14.wmv?tsid=20070803-164051-9d637d11";
>     //document.downloadForm.submit();
>   }
>   </script>
> </head>
> </html>http://www.2shared.com/download/1716611/e2000f22/
> Jadeed_Mlak14.3gp?tsid=20070803-164051-9d637d11"sfgsfgsfgv
>
> I use this pattern :
> "http.*?\.(wmv|3gp).*""
>
> but it returns only 'wmv' and '3gp' instead of "http://www.2shared.com/
> download/1716611/e2000f22/Jadeed_Mlak14.wmv?
> tsid=20070803-164051-9d637d11"
>
> what can I do? what's wrong whit this pattern? thanx for your comments

You could use r'window.location = "(.*?\.(wmv|3gp)";' as your regex
string, I guess..