Redo: How to create a function dynamically.

[Steven W. Orr]

I have this which works:

#! /usr/bin/python
strfunc = """
def foo( a ):
     print 'a = ', a
"""
exec strfunc
globals()['foo'] = foo
foo( 'Hello' )

and this which does not:

#! /usr/bin/python
import new
strfunc = """
def foo( a ):
     print 'a = ', a
"""
co = compile ( strfunc, '', 'exec' )
exec co
nfunc = new.function( co, globals(), 'foo' )
globals()['foo'] = nfunc
foo( 'Hello' )

When I try to run this one I get:
Traceback (most recent call last):
   File "./m2.py", line 13, in ?
     foo( 'Hello' )
TypeError: ?() takes no arguments (1 given)


I need the second case to work because I want to be able to end up with a 
function in a seperate module to do the work of function creation. The 
caller will pass in globals() so that the resulting function will end up 
in the directory?/dictionary? of that caller.

[And my apologies for overcomplicating the question on my first try.]

-- 
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steveo at syslang.net