Problem with filter()

[Boudreau, Emile]

Sorry folks my mistake def is_dev should be:
def is_Dev(stringy):
  stringx = stringy.split('-')
  if stringx[0] == '':
    if stringx[1] == r'win32':
      if stringx[2] == r'app':
        if stringx[4] == r'dev.tar.gz':
          return 1
 
But now the results of the filter is an empty list and i know it
shouldn't be.
 

Emile Boudreau 
________________________________

From: python-list-bounces+emile.boudreau=cognos.com at python.org
[mailto:python-list-bounces+emile.boudreau=cognos.com at python.org] On
Behalf Of Boudreau, Emile
Sent: Tuesday, April 03, 2007 10:52 AM
To: python-list at python.org
Subject: Problem with filter()



Hey all, 
        So I'm trying to filter a list with the built-in function
filter(). My list looks something like this: 
['logs', 'rqp-8.2.104.0.dep', 'rqp-8.2.93.0.dep',
'rqp-win32-app-8.2.96.0-inst.tar.gz',
'rqp-win32-app-8.2.96.0-inst.tar.gz']

Calling filter like this: compFiles = filter(is_Dev, compFiles) 
compFiles is my list and is_dev is the following 

def is_Dev(stringy): 
  print stringy 
  stringx = stringy.split('-') 
  if stringx[1] == r'win32': 
    if stringx[2] == r'app': 
      if stringx[4] == r'dev.tar.gz': 
        return 1 

For some reason I only get 'logs' printed when is_Dev is called. (ie.
It's only going through is_dev once) 
Does anyone see something wrong that I'm not seeing?? 

Thanks, 

Emile Boudreau 


 
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