Indentifying the LAST occurrence of an item in a list

[7stud]

On Apr 4, 10:55 am, "Terry Reedy" <tjre... at udel.edu> wrote:
> <tkp... at hotmail.com> wrote in message
>
> news:1175702329.330032.250750 at w1g2000hsg.googlegroups.com...
> | For any list x, x.index(item) returns the index of the FIRST
> | occurrence of the item in x. Is there a simple way to identify the
> | LAST occurrence of an item in a list? My solution feels complex -
> | reverse the list, look for the first occurence of the item in the
> | reversed list, and then subtract its index from the length of the list
> | - 1, i.e.
> |
> | LastOcc = len(x) - 1 - x[::-1].index(item)
> |
> | Is there a simpler solution?
>

How about:

l = [1, 2, 1, 3, 1, 5]
target = 1
for index, val in enumerate(l):
    if val==1:
        lastIndexOf = index

print lastIndexOf