try... except SyntaxError: unexpected EOF while parsing

[kyosohma at gmail.com]

On Apr 4, 12:38 pm, "oscartheduck" <oscarthed... at gmail.com> wrote:
> I have a small script for doing some ssh stuff for me. I could have
> written it as shell script, but wanted to improve my python skills
> some.
>
> RIght now, I'm not catching a syntax error as I'd like to.
>
> Here's my code:
>
> #!/usr/bin/env python
> import sys
> import os
>
> port = input("Please enter a port to connect on. If you're unsure or
> just want the default of port 2024 just hit enter  --  ")
>
> try:
>   if port > 65535:
>     print "That's not a valid port number, sorry. Between 0 and 65535
> is cool."
>     sys.exit()
>   else:
>     cmd = 'su root -c "/usr/sbin/sshd -p %s"' % port
> except SyntaxError:
>       cmd = 'su root -c "/usr/sbin/sshd -p 2024;exit"'
>
> os.system(cmd)
>
> I'm under the impression that the except should catch the syntax error
> and execute the "default" command, but hitting enter at the input
> value doesn't lead to that. Any ideas what's going wrong?

Try sticking your

port = input("Please enter a port to connect on. If you're unsure or
just want the default of port 2024 just hit enter  --  ")

inside your "try" block instead. Or switch to using the "raw_input"
builtin instead of "input".

Mike