On Apr 15, 9:49 pm, James Stroud <jstr... at mbi.ucla.edu> wrote: > py> t = timeit.Timer(stmt=s) > py> print "%.2f usec/pass" % (1000000 * t.timeit(number=100000)/100000) > 40.88 usec/pass > What does this accomplish: 1000000 * t.timeit(number=100000)/100000 that the following doesn't accomplish: 10 * t.timeit(number=100000)