__file__

[7stud]

Hi,

Thanks for the response.

On Apr 11, 12:49 am, "Gabriel Genellina" <gagsl-... at yahoo.com.ar>
wrote:
>
> __file__ corresponds to the filename used to locate and load the module,  
> whatever it is. When the module is found on the current directory  
> (corresponding to '' in sys.path), you get just the filename; if sys.path  
> contains a relative path, that's what you get; the same for any absolute  
> path.
> Whatever path worked to find and load the module, that's stored as  
> __file__.
>
> If you plan to use it, it's a good idea to make it early into an absolute  
> path (using os.path.abspath(__file__)) just in case the current directory  
> changes.
>

That last part doesn't seem to fit with your description above.  What
does the current working directory have to do with the path that was
used to load a module?  I would think the path that was used to load a
module is constant.