Indentifying the LAST occurrence of an item in a list

[Tim Williams]

On 4 Apr 2007 08:58:49 -0700, tkpmep at hotmail.com <tkpmep at hotmail.com> wrote:
> For any list x, x.index(item) returns the index of the FIRST
> occurrence of the item in x. Is there a simple way to identify the
> LAST occurrence of an item in a list? My solution feels complex -
> reverse the list, look for the first occurence of the item in the
> reversed list, and then subtract its index from the length of the list
> - 1, i.e.
>
> LastOcc = len(x) - 1 - x[::-1].index(item)
>
> Is there a simpler solution?

Simpler ?    That's subjective. :)

You definitely need to search/iterate a reversed list, or start from
the far end of a non-reversed list.

For fun only.

>>> t = [0,1,2,3,0]

>>> def place(t,i):
... 	for x,y in zip(t,range(len(t)))[::-1]:	
... 		if x == i:
... 			return y
... 		
>>> place(t,3)
3
>>> place(t,0)
4