printing longs
John Machin
sjmachin at lexicon.net
Fri Apr 6 18:19:25 EDT 2007
On Apr 7, 7:54 am, "garyp" <gary.por... at authentec.com> wrote:
> Python 2.3.4 (#1, Oct 26 2004, 16:42:40)
> [GCC 3.4.2 20041017 (Red Hat 3.4.2-6.fc3)] on linux2
>
> >>> x = int("80000000", 16)
> >>> x = x | 0x80000000
>
> <stdin>:1: FutureWarning: hex/oct constants > sys.maxint will return
> positive values in Python 2.4 and up
As your subject says, you are working with longs, so don't mix in an
int (0x8000000, which is negative in Python 2.3 and earlier) -- use
0x8000000L instead.
>
> >>> print "%x" % ( x )
> -80000000
"%x" % x
is enough.
>
> How do I get python to print the usual answer: 8000000, not -80000000
"usual" in what context?
Cheers,
John
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