iterator question

[dannycolligan at gmail.com]

Simple list comprehension?

>>> l = [1,2,3,4,5,6,7,8,9,0]
>>> [(x, x+1) for x in l if x%2 == 1]
[(1, 2), (3, 4), (5, 6), (7, 8), (9, 10)]

Danny

Neal Becker wrote:
> George Sakkis wrote:
>
> > johnzenger at gmail.com wrote:
> >
> >> def transform(seq, size):
> >>     i = 0
> >>     while i < len(seq):
> >>         yield tuple(seq[i:i+size])
> >>         i += size
> >
> > Or for arbitrary iterables, not just sequences:
> >
> > from itertools import islice
> > def transform(iterable, size):
> >      it = iter(iterable)
> >      while True:
> >          window = tuple(islice(it,size))
> >          if not window:
> > break
> >          yield window
> >
> > George
> > 
> 
> Thanks guys!
> 
> This one above is my personal favorite.