problem moving from char to integer

[John Machin]

Melih Onvural wrote:
> This is the error message that I'm having a tough time interpreting:
> Traceback (most recent call last):
>   File "pagerank.py", line 101, in ?
>     main()
>   File "pagerank.py", line 96, in main
>     ch = strord(url)
>   File "pagerank.py", line 81, in strord
>     result[counter] = int(i);
> ValueError: invalid literal for int(): i
>
> and here is the full code:
>
> def strord(url):
>     counter=0;
>     for i in url:
>        result[counter] = int(i);
>        counter += 1;
>
>     return result;

You are getting this error because you are trying to convert string to
integer, but this of course complains if it finds unexpected
non-digits.
int('9') -> 9
int('x') -> this error
You may be looking for the ord() function:
ord('9') -> 57
ord('x') -> 120

In any case, once you've sorted that out, your function will die in the
same statement, because "result" isn't defined. Python isn't awk :-)

Given the name of your function (strord), perhaps what you really want
is this:

def strord(any_string):
    return [ord(x) for x in any_string]

but why you'd want that (unless you were trying to pretend that Python
is C), I'm having a little troubling imagining ...

Perhaps if you told us what you are really trying to do, we could help
you a little better.

HTH,
John