Difference between two dates in seconds

[Rob Williscroft]

Steven D'Aprano wrote in
news:pan.2006.09.27.23.20.59.226695 at REMOVE.THIS.cybersource.com.au in
comp.lang.python: 

> On Wed, 27 Sep 2006 20:16:52 +0200, Fredrik Lundh wrote:
> 
>> Claes at work wrote:
>> 
>>> Please tell me there is a simpler way than subtracting two datetimes
>>> to get a timedelta and then compute
>>> 
>>> days * number of seconds per day + seconds
>>> 
>>> from it myself??
>> 
>> why would you have to do that yourself?  why not let Python do it for
>> you?  here's the code:
>> 
>>     seconds = td.days * 86400 + td.seconds
> 
> I'm sure somebody as experienced as Fredrik doesn't need to be told
> why peppering code with magic constants like 84600 are a less than
> ideal solution -- and for those who do need to be told, carefully
> compare what I wrote to what Fredrik wrote to see one of those
> reasons. 

What you wrote, where ?

> 
> Arguably a better solution would be to do this:
> 
> seconds = td.days * 24*60*60 + td.seconds
> 
> Still not ideal though, although that depends on just how often you
> need to convert days to or from seconds.
> 
> 



Rob.
-- 
http://www.victim-prime.dsl.pipex.com/