dictionary of list from a file

[Matthew Warren]

> -----Original Message-----
> From: 
> python-list-bounces+matthew.warren=digica.com at python.org 
> [mailto:python-list-bounces+matthew.warren=digica.com at python.o
> rg] On Behalf Of Giovanni Bajo
> Sent: 04 October 2006 15:17
> To: python-list at python.org
> Subject: Re: dictionary of list from a file
> 
> andrea.spitaleri at gmail.com wrote:
> 
> > while(<IN>){
> >           @info=split(/ +/,$_);
> >           push (@{$tmp{$info[0]}},$info[1]);
> > }
> >
> > and then
> > foreach $key (keys %tmp){
> >            print "$key -> @{$tmp{$key}}\n";
> > }
> 
> Python 2.5 introduced a dictionary type with automatic 
> creation of values,
> ala Perl:
> 
> ===============================
> from collections import defaultdict
> 
> d = defaultdict(list)
> for line in fl:
>      k, v = line.strip().split()
>      d[k].append(v)
> 
> for k,v in d.items():
>      print k, v
> ===============================
> 
> Notice that Python is always more strongly typed, so you have 
> to specify a
> factory function.


Yay! Python2.5 fixed my approach to this, I tried

from collections import defaultdict
f=file('c:\\test.txt')
lines=f.readlines()
f.close()
d=defaultdict(list)
[ d[l.split()[0]].append(l.split()[1]) for l in lines ]

But, if I try your (to see if I've actually got it right)

For k,v in d.items():
	print k,v

I get

AttributeError: 'list' object has no attribute 'items'




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