Problem getting a file pathname with tkFileDialog

[cdroulers at hotmail.com]

Hello,
I am working on a school project that requires me to get the path of a
filename for future treatment.
I've tried getting a file with tkFileDialog.askopenfile.


********************************************
import tkFileDialog
file = tkFileDialog.askopenfile()
print file
********************************************


It prints the opened files stuff, but I just can not find how to get
that path as a string. I've searched around google and the present
group, and found no documentation on the file class used with
tkFileDialog. Does someone have a solution for that?

Thank you

Christian